What is 45 percent of 330?
Answer: 45 percent of 330 is 148.5. Alternatively, we can say that 148.5 is equivalent to 45% of 330.
Solution for What is 45 percent of 330:
Now we have 45% of 330 = 148.5. Alternatively, we can express it as 45 percent of 330 equals 148.5.
The step-by-step process for finding what is 45 percent of 330:
The mathematical calculation of 45% of 330 can be broken down as follows:
- 45 percent * 330
- Convert this into an equation: (45 / 100) * 330
- Simplify the equation further: (45 * 330) / 100
- Carry out the calculation: 14850 / 100
- The final answer is: 148.5
Thus, we conclude that 45% of 330 is 148.5.
Explanation for What is 45% of 330:
Step 1: 45 percent * 330
Think of percent as parts out of 100. So, when we say 45 percent, it's like having 45 parts out of a total of 100. What we want to do now is find out what those 45 parts would be if our total was 330 instead of 100.
Step 2: (45 / 100) * 330
This is like dividing our 45 parts into 100. It's as if we have 100 pieces of candy and we only want 45 of those pieces. That gives us 0.45 or 45 hundredths. Now we multiply those 45 parts (or 0.45) by 330 to find out what 45% of 330 would be.
Step 3: (45 * 330) / 100
This is an alternative calculation. Instead of doing it in two steps like we did before, we can also do it in one step. First, we multiply 45 (our 45 parts) by 330 (our total amount), and then we divide that by 100.
Step 4: 14850 / 100
The previous step gave us 14850. But remember we were pretending our total was 100? Now we have to divide by 100 to get back to the number for our real total, which is 330. That's why we divide 14850 by 100.
Step 5: 148.5
Finally, after dividing 14850 by 100, we arrive at the answer: 148.5. Hence, we can definitively say that 45% of 330 equals 148.5.
This guide aims to simplify the understanding of percentage calculations, focusing on the question "What is 45% of 330?" Keep practicing with different numbers to hone your skills in percentage calculations. We hope this helps you in your quest for better mathematical understanding.
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